{"id":1479,"date":"2020-01-15T18:38:14","date_gmt":"2020-01-15T18:38:14","guid":{"rendered":"http:\/\/newgovjobs.in\/?p=1479"},"modified":"2023-07-20T20:34:12","modified_gmt":"2023-07-20T20:34:12","slug":"csir-net-result","status":"publish","type":"post","link":"https:\/\/newgovjobs.in\/csir-net-result\/","title":{"rendered":"CSIR NET RESULT 2020 – step by step process to check result"},"content":{"rendered":"\n

CSIR NET RESULT 2020: Council of Scientific and Industrial Research (CSIR) has officially released the CSIR NET RESULT 2020<\/strong>. An online test was conducted by CSIR UGC-NET\u00a0 to check the eligibility for JRF and Assistant Professor posts. All qualified candidates will be posted in Indian universities and colleges as per the eligibility criteria. \u00a0CSIR UGC-NET invites applications two times each year to fill vacant positions. Please check step by step process<\/strong> to check the CSIR net result 2020.<\/p>\n\n\n

Step1. Click here<\/a> to Visit NTA official website(See below image)<\/h2>\n\n\n
\"csir-nta-result\"<\/figure>\n\n\n

Step2- Move down and Click on \u201cView Score Card\u201d(See below image)<\/h2>\n\n\n
\"csir-nta-result2\"<\/figure>\n\n\n

Step3- Now you will get two options for login(See below image)<\/h2>\n\n\n